What Is the Output of This Java Code?
Question :
public class Main {
public static void main(String[] args) {
int x = 5;
System.out.println(x++ + ++x);
}
}
Options :
A) 10
B) 11
C) 12
D) 13
Correct answer :
C) 12
Explanation :
Step 1 - class declaration
public class Main
- public → Access modifier . this class can be accessed form anywhere.
- class → Used to create a class in java
- main → Name of the class
So this line creates a class called main.
Step 2 - main method :
public static void main(String[ ] args)
This is the entry point of every java program.
- public → Accessible form anywhere.
- static → JVM can call this method without creating an object.
- void → This methods does not return any value.
- main → Method name where the program starts.
- String[ ] args → Stores command line arguments.
So the program starts executing form this method.
Step 3 - create variable :
int x = 5;
- int → Integer data type.
- x → Variable name .
- = 5 → Assign value 5 to variable x.
Step 4 - print statement :
System.out.println(x++ + ++x);
Now break this line in to parts :
System → is a built-in Java class.
out → is an object of PrintStream used for printing output.
println() → prints the value and moves to the next line.
Step 5 - Evaluate expression :
Expression:
x++ + ++x
Initial value:
x = 5
Step 6 - Post Increment (X++) :
X++
Rule of post increment :
1. First use the value
2. Then increase it
So :
Use value = 5
x becomes = 6
Step 7 - Pre Increment (++x) :
++X
Rule of pre increment :
1. First increase the value
2. Then use it
Current value :
X = 6
After increment :
++x = 7
Step 8 - Final calculation :
Expression :
5 + 7
Result :
12
Final Output :
12
Key points :
X++ → Use value first then increment
++X → Increment first then use value
Practice daily Java coding challenges to improve your programming and logical thinking skills.
Happy coding ❤️
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